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A quadratic function f(x) = x^2 + bx +C has a vertex at (−2,1). Find the values of a, b and c. Show your work describe the strategy used.

Sagot :

Mhanifaidn

Answer:

  • a = 1, b = 4, c = 5

Step-by-step explanation:

The x-coordinate of the vertex is determined by:

  • x = -b/(2a)

So we have:

  • -2 = -b/(2a)
  • b = 4a = 4 since a = 1 (x² has no coefficient, so its 1)

Now, substitute x- and y- values to find the value of c:

  • 1 = (-2)² + 4(-2) + c
  • 1 = 4 - 8 + c
  • 1 = -4 + c
  • c = 1 + 4
  • c = 5
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