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FIND THE CENTRE OF GRAVITY OF AN INVERTED T-SECTION WITH FLANGE 60 mm x 10mm and WEB 50mm x 10mm​

Sagot :

Answer:

Explanation:

Assuming the material of the T-section is uniform, the weight of each portion will be proportional to the area and the CG of each portion will be at its geometric center.

From symmetry, the CG will be along the midline of the web

Area of flange 60(10) = 600 mm²

Area of web 50(10) = 500 mm²

let y be the position of the assembly CG.

Let the flange bottom be coincident on the x axis.

y(600 + 500) = 600(10/2) + 500(10 + 50/2)

1100y = 3000 + 17,500

y = 18.63636363...

y ≈ 18.6 mm

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