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•1 The floor of a railroad flatcar is loaded with loose crates hav- ing a coefficient of static friction of 0.25 with the floor. If the train is initially moving at a speed of 48 km/h, in how short a distance can the train be stopped at constant acceleration without causing the crates to slide over the floor?
The maximum friction force provides the most significant deceleration (of magnitude a) (With F n =mg in this case). Using Newton’s second law, we find a=f s, max /m=μ s g In this calculation, it is vital first to convert v = 48km/hr to 13m/s. This gives the shortest distance to stop:△x = v 2 /2a=36m.
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