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Find the slope of the line that is parallel to the graph of 2x+3y=5

Sagot :

Answer:

slope = - [tex]\frac{2}{3}[/tex]

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

2x + 3y = 5 ( subtract 2x from both sides )

3y = - 2x + 5 ( divide terms by 3 )

y = - [tex]\frac{2}{3}[/tex] x + [tex]\frac{5}{3}[/tex] ← in slope- intercept form

with slope m = - [tex]\frac{2}{3}[/tex]

Parallel lines have equal slopes

Then slope of parallel line is - [tex]\frac{2}{3}[/tex]

Janhavi11idn

Answer:

slope is -2/3

Step-by-step explanation:

General form of a straight line :- y = mx + c

Where , x and y are order pairs or coordinates.

m is slope of the line

c is y intercept.

Also,if the is line L2 with slope m2 is parallel with line L1 which has slope m1 then,

• m1 = m2

Here , 2x + 3y = 5

3y = -2x + 5

[tex]y = \frac{ - 2x + 5}{3} [/tex]

[tex]y = \frac{ - 2x }{3} + \frac{5}{3} [/tex]

so comparing the given equation with general form we get

slope (m ) = (-2/3)

and required line is parallel to given line so required slope is -2/3

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