Answered

IDNLearn.com connects you with experts who provide accurate and reliable answers. Our experts are ready to provide in-depth answers and practical solutions to any questions you may have.

Two parallel 60-N forces are applied as shown to the corners A and C of a 200-mm square plate. Determine the moment of the couple formed by the two forces (a) by multiplying their magnitude by their perpendicular distance, (b) by resolving each force into horizontal and vertical components and adding the moments of the two resulting couples

Sagot :

Okpalawalter8idn

We have that perpendicular distance and the two resulting couples

[tex]m=-16.39m\\\\m=16.39Nm(cw)[/tex]

From the question we are told that

Two parallel 60-N forces

A and C of a 200-mm square plate.

Generally the equation for AC   is mathematically given as

[tex]AC=\sqrt{0.2^2+(0.2^2)}\\\\AC=0.2\sqrt{2m}\\\\sin75=\frac{d}{AC}\\\\d=(0.2\sqrt{2})sin75\\\\d=0.2732m\\\\m=Fxd\\\\m=-60x0.2732m\\\\m=-16.39m[/tex]

b)

[tex]mFm=Fm*0.2\\\\mFm=-30V_3x0.2\\\\mF_m=-6v_3\\\\mF_v=-6Nm\\\\Thereforem=16.39Nm(cw)[/tex]

For more information on this visit

https://brainly.com/question/23366835?referrer=searchResults

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy and accurate answers, visit IDNLearn.com. Thanks for stopping by, and see you next time for more solutions.