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When a piece of metal is irradiated with UV radiation (λ = 162 nm), electrons are ejected with a kinetic energy of 3.54×10-19 J. What is the work function of the metal?

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We have that the work function of the metal

[tex]\phi=1.227*10^{-18}J[/tex]

From the Question we are told that

UV radiation (λ = 162 nm)

Kinetic energy [tex]K.E =3.54*10-19 J.[/tex]

Generally the equation for Kinetic energy    is mathematically given as

[tex]KE =\frac{hc}{\pi-\phi} \\\\\phi =\frac{ 6.626*10^{-34} * 3*10^8}{162*10^{-9} -3.54*10^{-19}}[/tex]

[tex]\phi=1.227*10^{-18}J[/tex]

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