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Solve The Following class=

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Answer:

[tex]x=2, \ y=1[/tex]

Step-by-step explanation:

[tex]\displaystyle \left \{ {{\text{Equation I:} \ \ 2x+y =5} \atop {\text{ Equation II:} \ \ 3x-2y=4}} \right.[/tex]

Multiply [tex]\text{Equation I}[/tex] by 2.

  • [tex]2 \ \Big{[}2x+y=5\Big{]}[/tex]  
  • [tex]4x+2y=10[/tex]

Now we have this system of equations:

  • [tex]\displaystyle \left \{ {{4x+2y =10} \atop {3x-2y=4}} \right.[/tex]

We can add the equations together to cancel out y.

  • [tex]7x=14[/tex]
  • [tex]x=2[/tex]

Substitute x = 2 into the first equation and solve for y.

  • [tex]2(2)+y=5[/tex]
  • [tex]4+y=5[/tex]
  • [tex]y=1[/tex]

The solution to this system of equations is:

  • [tex]x=2, \ y=1[/tex]
  • or [tex](2, \ 1)[/tex]
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