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Answer:
[tex]2\sqrt{5} . i - \sqrt{5}.j[/tex]
Explanation:
the unit vector of 2i-j
[tex]=\frac{1}{\sqrt{2^{2} +(-1)^{2} } }2i-j\\=\frac{1}{\sqrt{5} } (2i-j)[/tex]
The vector of magnitude 5 which is parallel to 2i - j is
[tex]5.\frac{1}{\sqrt{5} } (2i-j)\\=2\sqrt{5} . i - \sqrt{5}.j[/tex]