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Finding the density of solids requires a method of measuring the volume of the solid. If the solid has a regular geometric shape, the volume can be calculated from a measurement of the dimensions of the shape. Consider the Object B below. Given that its mass is 108.510 g and its dimensions are: diameter = 2.90 cm, height = 3.20 cm, what is the density of Object B (cylinder)?

Sagot :

Mohammed1819049idn

Explanation:

volume of cylinder is equal to A(area )h( height)

so 2.90*3×3.20=78cm*3

mass equal to 108.510g

so the density is

108.510/78=1.4g/cm/3

Dsdrajlinidn

The density of a cylinder whose mass is 108.510 g and its dimensions are diameter = 2.90 cm and height = 3.20 cm is 5.14 g/cm³.

Given the diameter (d) of 2.90 cm and the height (h) of 3.20 cm, we can calculate the volume (V) of the cylinder using the following expression.

[tex]V = \pi \times (\frac{d}{2} )^{2} \times h\\V = \pi \times (\frac{2.90cm}{2} )^{2} \times 3.20 cm = 21.1 cm^{3}[/tex]

Density (ρ) is an intrinsic property of matter and it is equal to the quotient between the mass (m) and the volume (V).

[tex]\rho = \frac{m}{V} = \frac{108.510 g}{21.1 cm^{3} } = 5.14 g/cm^{3}[/tex]

The density of a cylinder whose mass is 108.510 g and its dimensions are diameter = 2.90 cm and height = 3.20 cm is 5.14 g/cm³.

You can learn more about density here: https://brainly.com/question/24386693

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