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Sagot :
Explanation:
volume of cylinder is equal to A(area )h( height)
so 2.90*3×3.20=78cm*3
mass equal to 108.510g
so the density is
108.510/78=1.4g/cm/3
The density of a cylinder whose mass is 108.510 g and its dimensions are diameter = 2.90 cm and height = 3.20 cm is 5.14 g/cm³.
Given the diameter (d) of 2.90 cm and the height (h) of 3.20 cm, we can calculate the volume (V) of the cylinder using the following expression.
[tex]V = \pi \times (\frac{d}{2} )^{2} \times h\\V = \pi \times (\frac{2.90cm}{2} )^{2} \times 3.20 cm = 21.1 cm^{3}[/tex]
Density (ρ) is an intrinsic property of matter and it is equal to the quotient between the mass (m) and the volume (V).
[tex]\rho = \frac{m}{V} = \frac{108.510 g}{21.1 cm^{3} } = 5.14 g/cm^{3}[/tex]
The density of a cylinder whose mass is 108.510 g and its dimensions are diameter = 2.90 cm and height = 3.20 cm is 5.14 g/cm³.
You can learn more about density here: https://brainly.com/question/24386693
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