Explanation:
Correct option is
A
10
20
Given : I=1A,t=16s,e=1.6×10
−19
C
Step 1: Current drawn by the filament
I=
t
Q
=
t
Ne
(Since Q=Ne, where N is the number of electrons crossing in time t)
⇒N=
e
I t
....(1)
Step 2: Substituting the values in equation (1)
N=
e
I t
=
1.6×10
−19
C
1A×16s
=10
20
Hence, number of electrons passing through a cross section of the filament in 16 seconds would be 10
20
.
