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16.(2-3x)+x^2.(3x-2)=0

Sagot :

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Answer:

[tex] x_{1} = - 1 \: . \: \: x_{2} = \frac{2}{3} . \: \: x_{3} = 1 [/tex]

Step-by-step explanation:

[tex](2 - 3x) + {x}^{2} (3x - 2) = 0 \\ 2 - 3x + {x}^{3} - 2 {x}^{2} = 0 \\ - (3x - 2) + {x}^{2} (3x - 2) = 0 \\ - (3x - 2)(1 - {x}^{2} ) = 0 \\ (3x - 2)(1 - {x}^{2} ) = 0 \\ 3x - 2 = 0 \\ 1 - {x}^{2} = 0 \\ x = \frac{3}{2} \\ x = - 1 \\ x = 1 \\ [/tex]

[tex]\boxed{\green{ x_{1} = - 1 \: . \: \: x_{2} = \frac{2}{3} . \: \: x_{3} = 1}}[/tex]

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