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Answer:
Step-by-step explanation:
The foci:
F=(1,0)
F'=(-1,0)
The co-vertices:
V=(0,2
V'=(-2,0)
[tex]\dfrac{x^2}{a^2} +\dfrac{y^2}{b^2} =1\\\\with\ \\b=2\\and \\2*a=2*|FV|=2*\sqrt{5} \, a=\sqrt{5}\\\\\dfrac{x^2}{5} +\dfrac{y^2}{4} =1\\[/tex]