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Sagot :
There are five molecules of the water of crystallization.
Mass of hydrated copper(II) sulfate CuSO4 · xH2O = 0.755 g
Mass of anhydrous copper(II) sulfate CuSO4 = 0.483 g
Molar mass of hydrated copper(II) sulfate CuSO4 · xH2O = (160 + 18x) g/mol
Molar mass of anhydrous copper(II) sulfate CuSO4 =160 g/mol
Number of moles of hydrated copper(II) sulfate CuSO4 · xH2O = Number of moles of anhydrous copper(II) sulfate CuSO4
Therefore;
0.755 g/(160 + 18x) g/mol = 0.483 g/160 g/mol
0.755 * 160 = 0.483 (160 + 18x)
120.8 = 77.28 * 8.694x
120.8 - 77.28 = 8.694x
x = (120.8 - 77.28)/8.694
x = 5
The formula of the hydrated salt is CuSO4 · 5H2O.
Learn more; https://brainly.com/question/14252791
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