IDNLearn.com offers a unique blend of expert answers and community insights. Ask your questions and receive comprehensive, trustworthy responses from our dedicated team of experts.

Given g(x)=x² - 2x, find the equation of the secant line passing through (-4,g(-4)) and (1,g(1)). Write your answer in the form y=mx+b.


Sagot :

Answer:

[tex]y = -5x -2[/tex]

Step-by-step explanation:

Given:

[tex]g(x) = x^2 -2x[/tex]

Solving for [tex]\bold{g(-4)}[/tex]:

[tex]g(-4) = (-4)^2 -2(-4) \\ g(-4) = 16 +8 \\ g(-4) = 24[/tex]

This means that [tex](-4,g(-4))[/tex] is an equivalent statement of [tex](-4,24)[/tex].

Solving for [tex]\bold{g(1)}[/tex]:

[tex]g(1) = (1)^2 -2(1) \\ g(-4) = 1 -2 \\ g(-4) = -1[/tex]

This means that [tex](1,g(1))[/tex] is an equivalent statement of [tex](1,-1)[/tex].

Now we have the two points of the line, [tex](-4,24)[/tex] and [tex](1,-1)[/tex], we can finally solve for its slope, [tex]m[/tex]. Recall that [tex]m = \frac{y_2 -y_1}{x_2 -x_1}\\[/tex].

[tex]m = \frac{-1 -24}{1 -(-4)} \\ m = \frac{-25}{5} \\ m = -5[/tex]

Now that we know our slope, we can then write it as point-slope form and then rewrite it in its slope-intercept form as we are asked. Recall that an equation of a line in its point-slope form is write, [tex]y -y_1 = m(x -x_1)[/tex], where [tex]y_1[/tex] and [tex]x_1[/tex] is [tex]y[/tex] and [tex]x[/tex] coordinates of any point of a line respectively.

Writing for the equation of a line in its point-slope form with the point [tex]\bold{(1,-1)}[/tex]:

[tex]y -(-1) = -5(x -1) \\ y +1 = -5(x -1)[/tex]

Rewriting for the equation of a line in its slope-intercept form:

[tex]y +1 = -5(x -1) \\ y +1 = -5x -1 \\ y = -5x -2[/tex]

Thank you for using this platform to share and learn. Keep asking and answering. We appreciate every contribution you make. IDNLearn.com has the answers you need. Thank you for visiting, and we look forward to helping you again soon.