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Sagot :
Distance between them=100km
James started at 8:00 and Kumar at 8:30
Time difference=30min
Now apply physics
Time=30min
Speed=60km/h
[tex]\\ \rm\longmapsto Distance=Speed(Time)[/tex]
[tex]\\ \rm\longmapsto Distance=60\times \dfrac{1}{2}h=30km[/tex]
Now
Distance left =100km-30km=70km
Again
Distance=70km
Speed=60+50=110km/h
[tex]\\ \rm\longmapsto Time=\dfrac{Distance}{Speed}=\dfrac{70}{110}\approx38min[/tex]
Now assumed time=8:30+0:38=9:08(approx)
Both will cross each other at 9:08
Answer:
- 09 : 08 : 12
Step-by-step explanation:
James travels 30 min before Kumar starts to travel.
By this time James travels:
- 60 km/h *30 min =
- 60 km/h * 0.5 h = 30 km
At 8:30 the distance between them is:
- 100 km - 30 km = 70 km
Time to travel 70 by both:
- 70 km / (60 + 50) km/h =
- 70 /110 h =
- 7/11 h ≈ 38.2 min
James and Kumar pass each other at:
- 08:30 + 38.2 =
- 09: 08.2
or
- 09 : 08 : 12
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