Answered

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. A projectile is launched from a cliff 100m above level ground with a velocity of 30m/s at an
angle 20⁰ above the horizontal. Determine the projectile’s a) Range, b) pick height, c) velocity at
2s after launch.

Sagot :

Arlingrajidn

Answer:

How to find the maximum height of a projectile?

if α = 90°, then the formula simplifies to: hmax = h + V₀² / (2 * g) and the time of flight is the longest. ...

if α = 45°, then the equation may be written as: ...

if α = 0°, then vertical velocity is equal to 0 (Vy = 0), and that's the case of horizontal projectile motion.

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