Sukriti009idn
Answered

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Guys please answer this question best one with explanation will get brainiest and 5 start compete yourself with other
no 5 one there is answer but how that came

Guys Please Answer This Question Best One With Explanation Will Get Brainiest And 5 Start Compete Yourself With Other No 5 One There Is Answer But How That Came class=

Sagot :

Discipulusidn

Answer:

[tex] {( \sin(a) + \cos(a) )}^{2} + \\ {( \sin(a) - \cos(a) )}^{2} \\ {(a + b})^{2} = {a}^{2} + 2ab + {b}^{2} \\ {(a - b})^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]

[tex]

{(\sin(a)+ \cos(b)})^{2} = \\{\sin(a)}^{2} + 2\sin(a)\cos(b)\\ + {\cos(b)}^{2} \\ {(\sin(a) - \cos(b)})^{2} = \\{\sin(a)}^{2} - 2\sin(a)\cos(b) + {\cos(b)}^{2} [/tex]

[tex] 2\sin(a)\cos(b) cancel :\ out\\[/tex]

[tex] =2{\sin}^{2}(a) +2{\cos}^{2}(a) [/tex]

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