We have that the probability of Janice rolling a 2 or 5 on her 7th toss of the dice is
[tex]\frac{1}{3}^7.[/tex]
From the question we are told that
Janice rolled either a 2 or a 5 on the last 6 rolls of the die
Janice rolling a 2 or 5 on her 7th toss of the dice
[tex]P(2/ 5)=1/6+1/6\\\\P(2/ 5)=2/6\\\\P(2/ 5)=1/3.[/tex]
Where
[tex]P(2/5 ) =(1/3)^6.[/tex]
Janice roll the standard die 7th time the probability of getting 2 or 5 is
[tex]P(2/5 ) =\frac{1}{3}^7.[/tex]
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