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A van is traveling with an initial velocity of 12 m/s. The driver takes a time of 45 seconds to speed up to a velocity of 20 m/s. How much distance did the van cover during this time?

Sagot :

  • Initial velocity=u=12m/s
  • Final velocity=v=20m/s
  • Time=t=45s

[tex]\\ \rm\hookrightarrow Acceleration=\dfrac{v-u}{t}[/tex]

[tex]\\ \rm\hookrightarrow Acceleration=\dfrac{20-12}{45}[/tex]

[tex]\\ \rm\hookrightarrow Acceleration=\dfrac{8}{45}[/tex]

[tex]\\ \rm\hookrightarrow Acceleration=0.1m/s^2[/tex]

Now

  • Distance=s

[tex]\\ \rm\hookrightarrow v^2-u^2=2as[/tex]

[tex]\\ \rm\hookrightarrow (20)^2-12^2=2(0.1)s[/tex]

[tex]\\ \rm\hookrightarrow 400-144=0.2s[/tex]

[tex]\\ \rm\hookrightarrow 256=0.2s[/tex]

[tex]\\ \rm\hookrightarrow s=\dfrac{256}{0.2}[/tex]

[tex]\\ \rm\hookrightarrow s=1280m[/tex]

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