The required equation is [tex]8+\dfrac{n}{3}=-2[/tex] and the required unknown number is [tex]n=-30[/tex].
Given:
The statement is "Eight plus the quotient of a number and 3 is -2".
To find:
The required equation and the value of the variable [tex]n[/tex].
Solution:
Let [tex]n[/tex] be the unknown number.
Quotient of a number and 3 is [tex]\dfrac{n}{3}[/tex].
Eight plus the quotient of a number and 3 is [tex]8+\dfrac{n}{3}[/tex].
It is given that eight plus the quotient of a number and 3 is -2. So,
[tex]8+\dfrac{n}{3}=-2[/tex]
The required equation is [tex]8+\dfrac{n}{3}=-2[/tex]
Multiply both sides by 3.
[tex]24+n=-6[/tex]
Subtracting 24 from both sides, we get
[tex]24+n-24=-6-24[/tex]
[tex]n=-30[/tex]
The required unknown number is [tex]n=-30[/tex].
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