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Mr. Kent drove to a conference. The first half in distance of the trip took 3 hours due to traffic. Traffic let up for the second half of the trip and he was able to increase his average speed by 20 mph to make sure he got there in time. Find his average rates of speed for each half of the trip if he traveled for two hours at the second rate.

Sagot :

Fichohidn

The travel rates are :

  • With traffic = 40 mph
  • Without traffic = 60 mph

Recall :

Distance = speed × time

With traffic :

Time taken = 3 hours

Average speed = d

Distance = 3 × d = 3d ---(1)

Without traffic :

Time taken = 2 hours

Average Speed = 20 + d

Distance = 2(20 + d) - - - (2)

Equating (1) and (2)

3d = 2(20 + d)

3d = 40 + 2d

3d - 2d = 40

d = 40

The rates for each half :

With traffic = 40 mph

Without traffic = 40 + 20 = 60 mph

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