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From the construction, quadrilateral ACBD is a rhombus because circles A and B have the same radius.
A chord is a line that do not pass though the center of a circle and joins two points on its circumference. It majorly divides the circumference of a circle into major and minor arcs.
With the given conditions in the question, quadrilateral ACBD sides ae chords. As regards the circles, sides AC and AD are chords circle B. Also, CB and BD are chords on circles A. So that the sides of quadrilateral ACBD are equal.
The main reason why the quadrilateral is a rhombus is because circles A and B have the same diameter, thus the same radius.
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