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What is the daughter nucleus (nuclide) produced when 213 Bi undergoes alpha decay? Replace the question marks with the
proper integers or symbols.

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The daughter nucleus (nuclide) produced is [tex]\frac{209}{79} Au[/tex]

When an alpha decay occurs, the daughter nucleus has its atomic number less than that of the parent nucleus by two units and its mass number less than that of the parent nucleus by four units.

If we write the nuclear equation, we will have;

[tex]\frac{213}{83} Bi -----> \frac{209}{79} Au + \alpha[/tex]

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