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f(x)=x^4+mx^2+4, (x-1) is a factor, find m

Sagot :

Answer:

m= -5

Step-by-step explanation:

x⁴+mx²+4 =1* x⁴+0*x³+mx²+0*x+4

                = (x-1) (x³+ax²+bx-4)

                = x⁴ + (a-1)x³ + (b-a)x² - (b+4)x +4

(a-1)x³ vs 0*x³: a-1=0              a=1

- (b+4)x vs 0*x:   - (b+4)=0     b= -4

(b-a)x² vs mx²: b-a = m = -4-1 = -5

Check: x-1=0  x=1

            f(1) = 1⁴+ (-5)*1²+4 = 1-5+4 = 0