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[tex]here \: xo = yo = b \\ then \: according \: to \: pythagorean \: theorom \\ {(zx)}^{2} = {(xy)}^{2} + {(yz)}^{2} \\ {41}^{2} = {(2b)}^{2} + {9}^{2} \\ 1681 = 4 {b}^{2} + 81 \\ 1681 - 81 = 4 {b}^{2} \\ 1600 = 4 {b}^{2} \\ {b}^{2} = 1600 \div 4 = 400 \\ b = \sqrt{400} = 20cm \\ thank \: you[/tex]