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A rectangle with a width of x + 5 and a length of 6, has the same perimeter as a square with a side of x – 8.

Find the perimeter of the rectangle.

Perimeter of rectangle: P = 2L + 2W; Perimeter of square: P = 4s
x =
Perimeter of rectangle =

Sagot :

Answer:

Perimeter of rectangle is [tex]\[76\]m[/tex]

Step-by-step explanation:

Width of rectangle=[tex]\[x+5\][/tex]

Length of rectangle = [tex]\[6\][/tex]

Side of square = [tex]\[x-8\][/tex]

It is given that Perimeter of rectangle = Perimeter of square

[tex]\[2(l+b)=4s\][/tex]

Thus,

[tex]\[2(6+(x+5))=4(x-8)\][/tex]

Therefore,

[tex]& 2(11+x)=4x-32 \\ & 22+2x=4x-32 \\ & 22+32=4x-2x \\ & 54=2x \\ & x=27 \\[/tex]

Therefore, perimeter of rectangle is –

[tex]& =2(6+(x+5)) \\ & =2(6+(27+5)) \\ & =2(38) \\ & =76 \\[/tex]

Learn more about perimeter of square and rectangle: https://brainly.com/question/19355727?referrer=searchResults

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