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Sagot :
Answer:
The speed of mosquito over the ground is [tex]$4m/sec$[/tex].
Explanation:
• Relative velocity is defined as the velocity of an object B in the rest frame of another object A.
• To find the speed of mosquito over the ground, use this formula:
[tex]${V_{{M \mathord{\left/ {\vphantom {M A}} \right[/tex].
[tex]\kern-\nulldelimiterspace} A}}} = {V_{{M \mathord{\left/ {\vphantom {M G}} \right. \kern-\nulldelimiterspace} G}}} + {V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}}$[/tex]
Where [tex], $A$[/tex] represents air,[tex]$M$[/tex] represents mosquito and [tex]$G$[/tex] represents ground, thus [tex]${V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}}$[/tex] represents velocity of air with respect to ground and so on.
[tex]\\${V_{{M \mathord{\left/ {\vphantom {M A}} \right. \kern-\nulldelimiterspace} A}}} = 2m/sec$ \\${V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}} = - 2m/sec$[/tex]
• Placing the value of the given in the above formula.
[tex]& {V_{{M \mathord{\left/ {\vphantom {M A}} \right. \kern-\nulldelimiterspace} A}}} = {V_{{M \mathord{\left/ {\vphantom {M G}} \right.[/tex]
[tex]\kern-\nulldelimiterspace} G}}} + {V_{{A \mathord{\left/ {\vphantom {A G}} \right. \kern-\nulldelimiterspace} G}}} \\ & \Rightarrow 2 = {V_{{M \mathord{\left/ {\vphantom {M G}} \right. \kern-\nulldelimiterspace} G}}} - 2 \\[/tex]
[tex]& \Rightarrow {V_{{M \mathord{\left/ {\vphantom {M G}} \right. \kern-\nulldelimiterspace} G}}} = 4m/sec \\\end{align}\]$[/tex]
• Hence, the speed of mosquito over the ground is [tex]$4m/sec$[/tex].
Learn more about velocity here:
https://brainly.com/question/18026124
We have that the speed over the ground of a mosquito flying 2 m/s relative to the air against a 2 m/s headwind is
X=0m/s
From the question we are told that
mosquito flying 2 m/s
against a 2 m/s headwind
Generally
The speed over the ground is the Flight Speed minus resistance speed
Generally the equation for the speed over the ground is mathematically given as
X=Flight Speed-resistance speed
Therefore
X=2-2
X=0m/s
For more information on this visit
https://brainly.com/question/22271063?referrer=searchResults
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