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Kim, Eduardo, Katrina, Simone, Sergio, Jim, Maria, and Larry have all been invited to a dinner party. They arrive randomly and each person arrives at a different time. In how many ways can Kim arrive first and Larry last?

Sagot :

Answer:

# of ways to succeed:: 3! = 6

# of possible arrangements:: 5!

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Ans: 6/5! = 0.05