IDNLearn.com connects you with a community of knowledgeable individuals ready to help. Get the information you need from our community of experts, who provide detailed and trustworthy answers.
Sagot :
Answer: 1.22x10^78 H atoms per Universe
Explanation: Lots of conversions, so watch for errors.
Mass of Sun:
V=(4/3)πr²
V = (4/3)(π)(7x10⁸m)² = 1.44x10²⁷ m³ or 1.44x10³³ cm³
Mass of Sun: (1.44x10³³ cm³)*(1.4g/cm³) = 2.02x10³³ g/sun
Suns/Milky Way = 1x10¹¹ suns/galaxy
Suns/Universe = (1x10¹¹ suns/galaxy)*(1x10¹⁰galaxies/universe) = 1x10²¹ suns/universe
Assunming all mass ins in the suns, mass of the universe is:
(1x10²¹ suns/universe)*(2.02x10³³ g/sun) = 2.02x10⁵⁴g/universe
Molar mass of H is 1 g/mole
1 mole = 6.02x10²³H atoms
H atoms/universe = (2.02x10⁵⁴g/universe)*(1 g H atoms/mole)*(6.02x10²³H atoms/mole) = 1.22x10⁷⁸ H atoms per universe.
Answer:
Number of atoms in the universe is [tex]\[1.201\times {{10}^{79}}\][/tex]
Explanation:
Calculate number of atoms in universe using CGS unit.
Step 1
Calculate mass of sun
[tex]\[\text{Mass of sun = Density }\times \text{ Volume}\][/tex]
Step 2
Insert the value of density and radius to calculate mass of sun
[tex]& \text{Mass of sun = 1}\text{.4}\times \frac{4}{3}\pi {{\left( 7\times {{10}^{10}} \right)}^{3}} \\ & \text{Mass of sun}=2.011\times {{10}^{33}}g \\ \end{align}[/tex]
Average atomic mass of hydrogen atom is [tex]\[1.008amu\][/tex]
Avogadro’s number is number of atoms in 1 mole of hydrogen.
Step 3
Calculate number of Hydrogen [tex]\[\left( {{N}_{H}} \right)\][/tex]atoms in sun
[tex]& {{N}_{H}}=\frac{\text{Mass of sun}}{\text{Molar mass of Hydrogen atom}}\times \text{Avogadro }\!\!'\!\!\text{ s }\text{Number} \\ & {{N}_{H}}=\frac{2.011\times {{10}^{33}}}{1.008}\times 6.02\times {{10}^{23}} \\ & {{N}_{H}}=1.201\times {{10}^{57}} \\[/tex]
Step 4
Calculate number of atoms[tex]\[\left( {{N}_{A}} \right)\][/tex] in our Milky Way galaxy
[tex]& {{N}_{A}}=\text{Number of stars}\times \text{Number of atoms in sun} \\ & {{N}_{A}}=1.00\times {{10}^{11}}\times 1.202\times {{10}^{57}} \\ & {{N}_{A}}=1.201\times {{10}^{68}} \\[/tex]
Step 5
Calculate number of atom in observable universe [tex]\[\left( {{N}_{Ao}} \right)\][/tex]
[tex]& {{N}_{Ao}}=\text{Number of galaxies }\times \text{ Number of atoms in our galaxy} \\ & {{N}_{Ao}}=1.00\times {{10}^{11}}\times 1.201\times {{10}^{68}} \\ & {{N}_{Ao}}=1.201\times {{10}^{79}} \\[/tex]
Learn more about universe here:
https://brainly.com/question/17525451
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.