Answered

Find answers to your most challenging questions with the help of IDNLearn.com's experts. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.

Salmon often jump waterfalls to reach their
breeding grounds.
Starting downstream, 3.17 m away from a
waterfall 0.432 m in height, at what minimum
speed must a salmon jumping at an angle of
30.8º leave the water to continue upstream?
The acceleration due to gravity is 9.81 m/s?.
Answer in units of m/s.

Sagot :

Onyebuchinnajiidn

The minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.

The given parameters;

  • height of the waterfall, h = 0.432 m
  • distance of the Salmon from the waterfall, s = 3.17 m
  • angle of projection of the Salmon, = 30.8º

The time of motion to fall from 0.432 m is calculated as;

[tex]h = v_0_y + \frac{1}{2} gt^2\\\\0.432 = 0 + (0.5\times 9.8)t^2\\\\0.432 = 4.9t^2\\\\t^2 = \frac{0.432}{4.9} \\\\t^2 = 0.088\\\\t = \sqrt{0.088} \\\\t = 0.3 \ s[/tex]

The minimum velocity of the Salmon jumping at the given angle is calculated as;

[tex]X = v_0_x t\\\\3.17 = (v_0\times cos(30.8)) \times 0.3\\\\10.567 = v_0\times cos(30.8)\\\\v_0 = \frac{10.567}{cos(30.8)} \\\\v_0 = 12.3 \ m/s[/tex]

Thus, the minimum velocity of the Salmon jumping at the given angle is 12.3 m/s.

Learn more here: https://brainly.com/question/20064545

We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. For trustworthy answers, rely on IDNLearn.com. Thanks for visiting, and we look forward to assisting you again.