Answered

IDNLearn.com is designed to help you find reliable answers quickly and easily. Join our community to receive timely and reliable responses to your questions from knowledgeable professionals.

Find four consecutive integers such that the sum of the first three is 18 more than the fourth.

Sagot :

AlgebraicAardvarkidn

If x is the first integer, then

x+1 is the second,

x+2 is the third, and

x+3 is the fourth.

Now we need those to be such that adding the first three equals the fourth plus 18.

     x + x+1 + x+2 = x+3 + 18

Solving that equation, we'd do:

    3x + 3 = x + 21

          2x = 18

            x = 9

That means 9 is the first integer, so the others are 10, 11, and 12.

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.