Answered

Get expert insights and community-driven knowledge on IDNLearn.com. Ask anything and receive comprehensive, well-informed responses from our dedicated team of experts.

Find four consecutive integers such that the sum of the first three is 18 more than the fourth.

Sagot :

AlgebraicAardvarkidn

If x is the first integer, then

x+1 is the second,

x+2 is the third, and

x+3 is the fourth.

Now we need those to be such that adding the first three equals the fourth plus 18.

     x + x+1 + x+2 = x+3 + 18

Solving that equation, we'd do:

    3x + 3 = x + 21

          2x = 18

            x = 9

That means 9 is the first integer, so the others are 10, 11, and 12.

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. Accurate answers are just a click away at IDNLearn.com. Thanks for stopping by, and come back for more reliable solutions.