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Answer:
x < -√6 or √6 < x
Step-by-step explanation:
You want ...
2x^2 -3 > 9
2x^2 > 12 . . . . . add 3
x^2 > 6 . . . . . . . divide by 2
|x| > √6 . . . . . . . take the square root
This resolves into two disjoint sets:
x < -√6 or √6 < x
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In set notation, this might be ...
{x | x < -√6 ∪ √6 < x}