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if the discriminant is positive then the solution will be:

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If the discriminant, b^2 — 4ac is positive (or > 0), then the solution will be two (2) distinct real solutions.

If the discriminant is positive ( > 0), there are 2 real solutions.
If the discriminant is = 0, there is 1 real repeated solution.
If the discriminant is negative (< 0), there are 2 complex solutions (but no real solutions).
VectorFundament120idn

Answer:

Solutions have 2 real roots.

Step-by-step explanation:

Discriminant determines the solutions of quadratic equation.

If the value of discriminant is greater than 0 or D > 0 or D is positive then there are 2 real roots.

If the value of discriminant is 0, there is one real root.

If the value of discriminant is less than 0 or in negative then there are no real roots.

Formula

Discriminant can be found using:

[tex] \displaystyle \large{D = {b}^{2} - 4ac}[/tex]

The discriminant derives from Quadratic Formula.

[tex] \displaystyle \large{x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac } }{2a} }[/tex]

Now you should know why D > 0 gives 2 real roots because of ± which determines 2 solutions.

D = 0 gives one real root because x would be -b/2a

D < 0 gives no real roots because in square root, the value is negative which does not exist in real number.

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