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The family of this graph?

The Family Of This Graph class=

Sagot :

Answer:

Step-by-step explanation:

The shape of this graph is that of a parabola.  In this case the parabola opens down.  The general form of the equation of such a parabola is

y = a(x - h)^2 + k, where (h, k) is the vertex and a is a coefficient to be determined.

In this particular case we can obtain the coordinates of the vertex (h, k) from the graph.  They are (3, 4).  Thus, h = 3 and k = 4.  The graph goes through (1.5, 0).  Use this information to determine the value of the coefficient a:

Then the equation of this parabola must be y = a(x - 3)^2 + 4.

0 = a(1.5 - 3)^2 + 4

Then:

0 = a(-1.5)^2 + 4, or

0 = 2.25a + 4, or

2.25a = -4, or

a = 16/9

Thus, the final result:  The equation of this parabola is

y = (16/9)(x - 3)^2 + 4

whose graph is a parabola that opens down and has vertex (3, 4).