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Answer:
[tex]y = \frac{1}{8} x - 2 \frac{1}{4} [/tex]
Step-by-step explanation:
Slope-intercept form
y= mx +c, where m is the slope and c is the y-intercept
Line p: y= -8x +6
slope= -8
The product of the slopes of perpendicular lines is -1. Let the slope of line q be m.
m(-8)= -1
m= -1 ÷(-8)
m= ⅛
Substitute m= ⅛ into the equation:
y= ⅛x +c
To find the value of c, substitute a pair of coordinates that the line passes through into the equation.
When x= 2, y= -2,
-2= ⅛(2) +c
[tex] - 2 = \frac{1}{4} + c[/tex]
[tex]c = - 2 - \frac{1}{4} [/tex]
[tex]c = - 2 \frac{1}{4} [/tex]
Thus, the equation of line q is [tex]y = \frac{1}{8} x - 2 \frac{1}{4} [/tex].