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If m(x)=3(x² +5)+61, what is the value of m(12)?

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Answer:

[tex]m(x) = 3( {x}^{2} + 5) + 61 \\m(12) = 3( {12}^{2} + 5) + 61 \\ = 3(144 + 5) + 61 \\ = 3(149) + 61 \\ = 447 + 61 \\ = 508 [/tex]

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