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Subtract the second expression from the first.


Subtract The Second Expression From The First class=

Sagot :

Answer:

Solution :-

i) Given expressions are 2a + b, a + b

On Subtracting second expression form the first expression

=> (2a+b) -(a+b)

=> 2a+b-a-b

=> (2a-a)+(b-b)

=> a+0

=> a

ii) Given expressions are - 2b + 2c, b + 3c

On Subtracting second expression form the first expression

=> (- 2b + 2c)-( b + 3c)

=> -2b+2c-b-3c

=> (-2b-b)+(2c-3c)

=> -3b-c

iii) Given expressions are 5a + b, - 6b + 2a

On Subtracting second expression form the first expression

=> (5a + b)-(- 6b + 2a )

=> 5a+b+6b-2a

=> (5a-2a)+(b+6b)

=> 3a+7b

iv) Given expressions are a³-1+a, 3a-2a²

On Subtracting second expression form the first expression

=> (a³-1+a)-(3a-2a²)

=> a³-1+a-3a+2a²

=> a³-1-2a+2a²

=> a³+2a²-2a+1

v) Given expressions are p + 2,1

On Subtracting second expression form the first expression

=> (p+2)-(1 )

=> p+2-1

=> p+1

vi) Given expressions are x + 2y + z , -x - y - 3z

On Subtracting second expression form the first expression

=> (x + 2y + z )-(-x - y - 3z )

=> x+2y+z+x+y+3z

=> (x+x)+(2y+y)+(z+3z)

=> 2x+3y+4z

vii) Given expressions are 3a²-8ab-2b²,3a²-4ab+6b²

On Subtracting second expression form the first expression

=> (3a²-8ab-2b²)-(3a²-4ab+6b²)

=> 3a²-8ab-2b²-3a²+4ab-6b²

=> (3a²-3a²)+(-8ab+4ab)+(-2b²-6b²)

=> 0+(-4ab)+(-8b²)

=> -4ab-8b²

viii) Given expressions are 4pq-6p²-2q²,9p²

On Subtracting second expression form the first expression

=> (4pq-6p²-2q²)-(9p²)

=> 4pq-6p²-2q²-9p²

=> 4pq-15p²-2q²

ix) Given expressions are 10abc,2a²+2abc-4b²

On Subtracting second expression form the first expression

=> (10abc)-(2a²+2abc-4b²)

=> 10abc-2a²-2abc+4b²

=> 8abc-2a²+4b²

x) Given expressions are a²+ab+c², a²-d²

On Subtracting second expression form the first expression

=> (a²+ab+c²)-( a²-d²)

=> a²+ab+c²-a²+d²

=> (a²-a²)+ab+c²+d²

=> 0+ab+c²+d²

=> ab+c²+d²

Hope this helps!!