Suprinamaharjan95idn
Answered

IDNLearn.com provides a seamless experience for finding and sharing answers. Our Q&A platform is designed to provide quick and accurate answers to any questions you may have.

the present population of a certain place is 67205 the population growth rate is 5% per annum find the population of that place a year before​

Sagot :

Daichi1112008idn

Answer:

Let P be the population two years ago.

∴ P(1+

100

5

)

2

=104832

P(

100

105

)

2

=104832

P×

100

105

×

100

105

=104832

P=

105×105

104832×100×100

=95085.71

=95,086 (rounding off to the nearest whole number)

∴ Two years ago the population was 95,086.

Step-by-step explanation:

따 르 디 ➪ 엔 씨 티 Dream

https://youtu.be/PkKnp4SdE-w

Answer:

Step-by-step explanation:

∴ P(1+

100

5

)

2

=104832

P(

100

105

)

2

=104832

P×

100

105

×

100

105

=104832

P=

105×105

104832×100×100

=95085.71

=95,086 (rounding off to the nearest whole number)

∴ Two years ago the population was 95,086.

Thank you for using this platform to share and learn. Don't hesitate to keep asking and answering. We value every contribution you make. Thanks for visiting IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more helpful information.