Suprinamaharjan95idn
Answered

Discover new perspectives and gain insights with IDNLearn.com's diverse answers. Discover in-depth and reliable answers to all your questions from our knowledgeable community members who are always ready to assist.

the present population of a certain place is 67205 the population growth rate is 5% per annum find the population of that place a year before​

Sagot :

Daichi1112008idn

Answer:

Let P be the population two years ago.

∴ P(1+

100

5

)

2

=104832

P(

100

105

)

2

=104832

P×

100

105

×

100

105

=104832

P=

105×105

104832×100×100

=95085.71

=95,086 (rounding off to the nearest whole number)

∴ Two years ago the population was 95,086.

Step-by-step explanation:

따 르 디 ➪ 엔 씨 티 Dream

https://youtu.be/PkKnp4SdE-w

Answer:

Step-by-step explanation:

∴ P(1+

100

5

)

2

=104832

P(

100

105

)

2

=104832

P×

100

105

×

100

105

=104832

P=

105×105

104832×100×100

=95085.71

=95,086 (rounding off to the nearest whole number)

∴ Two years ago the population was 95,086.

We greatly appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.