Answered

At IDNLearn.com, find answers to your most pressing questions from experts and enthusiasts alike. Explore thousands of verified answers from experts and find the solutions you need, no matter the topic.

Michelle has two fair 3-sided spinners. Michelle spins each spinner once. Each spinner lands on a number. Michelle multiplies these two numbers together to get her score. Work out the probability that Michelle’s score is at least 8

Sagot :

Novastar9idn
What are the numbers on the 3 sides of the spinners?

Using probability of independent events, it is found that there is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this problem:

  • Two fair 3-sided spinners are span, and their values are multiplied.
  • The only way to get an score of at least 8 is spinning two threes.
  • For each spinner, there is a [tex]\frac{1}{3}[/tex] probability of spinning a 3, and the spinners are independent.

Hence:

[tex]P(A \cap B) = P(A)P(B) = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}[/tex]

There is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

You can learn more about independent events at https://brainly.com/question/25715148

We are delighted to have you as part of our community. Keep asking, answering, and sharing your insights. Together, we can create a valuable knowledge resource. IDNLearn.com is your reliable source for accurate answers. Thank you for visiting, and we hope to assist you again.