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Michelle has two fair 3-sided spinners. Michelle spins each spinner once. Each spinner lands on a number. Michelle multiplies these two numbers together to get her score. Work out the probability that Michelle’s score is at least 8

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Novastar9idn
What are the numbers on the 3 sides of the spinners?

Using probability of independent events, it is found that there is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this problem:

  • Two fair 3-sided spinners are span, and their values are multiplied.
  • The only way to get an score of at least 8 is spinning two threes.
  • For each spinner, there is a [tex]\frac{1}{3}[/tex] probability of spinning a 3, and the spinners are independent.

Hence:

[tex]P(A \cap B) = P(A)P(B) = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}[/tex]

There is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

You can learn more about independent events at https://brainly.com/question/25715148

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