Answered

IDNLearn.com is your go-to resource for finding expert answers and community support. Our community is here to provide detailed and trustworthy answers to any questions you may have.

Michelle has two fair 3-sided spinners. Michelle spins each spinner once. Each spinner lands on a number. Michelle multiplies these two numbers together to get her score. Work out the probability that Michelle’s score is at least 8

Sagot :

Novastar9idn
What are the numbers on the 3 sides of the spinners?

Using probability of independent events, it is found that there is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

If two events, A and B, are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this problem:

  • Two fair 3-sided spinners are span, and their values are multiplied.
  • The only way to get an score of at least 8 is spinning two threes.
  • For each spinner, there is a [tex]\frac{1}{3}[/tex] probability of spinning a 3, and the spinners are independent.

Hence:

[tex]P(A \cap B) = P(A)P(B) = \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}[/tex]

There is a [tex]\frac{1}{9} = 0.1111[/tex] probability that Michelle’s score is at least 8.

You can learn more about independent events at https://brainly.com/question/25715148

We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Your search for answers ends at IDNLearn.com. Thank you for visiting, and we hope to assist you again soon.