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Answer:
16 and 4
Step-by-step explanation:
x + y= 20
x -y =12
(add both equal #'s)
2x =32
x = 16
y=4
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Answer:
4 and 16
Step-by-step explanation:
First, let's find first term using sum formula:
[tex] \displaystyle \large{S_n = \frac{1}{2} n[2a_1 + (n - 1)d]}[/tex]
We know that d or common difference is 12 and only sum of two terms so n = 2.
[tex] \displaystyle \large{S_2 = \frac{1}{2} (2)[2a_1 + (2- 1)d]} \\ \displaystyle \large{S_2 = 2a_1 +d}[/tex]
Since sum of two numbers equal 20.
[tex] \displaystyle \large{20 - 12= 2a_1 +12 - 12} \\ \displaystyle \large{8= 2a_1 }[/tex]
From above, subtract both sides by 12, solving for a1.
[tex] \displaystyle \large{8= 2a_1 } \\ \displaystyle \large{4= a_1 } [/tex]
Therefore our first number is 4.
Finding next number, create an equation:-
[tex] \displaystyle \large{4 + a_2 = 20 } \\ \displaystyle \large{4 - 4 + a_2 = 20 - 4} \\ \displaystyle \large{ a_2 = 16 } [/tex]
Another number is 16
So 4 and 16 has 12 as difference because 4+12=16 and 16-12 = 4