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The number 8A3BC5 is a perfect square of a number that is divisible by 3. Find A + B + C if A, B, and C are different digits.
The number is divisible by 9 since the square root is divisible by 3. A+B+C+8+3+5 is a multiple of 9. There are only two sums that are divisble by 9. The number either adds up to 36 or 27. A+B+C add up to 20 or 11. 20 doesn't work since its not a square so the answer is 11.
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