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Aplicando la función, los valores numéricos son :
[tex]f(5) = -11[/tex]
[tex]f(4) = -12[/tex]
[tex]f(6) = -10[/tex]
[tex]f(3) = -13[/tex]
La función es dada por:
[tex]f(x) = (\sqrt{x})^2 - 16 = x - 16[/tex]
Para los valores numéricos, reemplazamos x, luego:
[tex]f(5) = 5 - 16 = -11[/tex]
[tex]f(4) = 4 - 16 = -12[/tex]
[tex]f(6) = 6 - 16 = -10[/tex]
[tex]f(3) = 3 - 16 = -13[/tex]
Un problema similar es dado en https://brainly.com/question/7037337