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The highest involuntary deceleration survived by a human is 1762 m/s2. Formula-1 racecar driver David Purley crashed into a wall going 110 mph. How much distance in meters was covered during this massive deceleration? Report answer with two significant digits and do not forget units.

Sagot :

The kinematics can be found that for the stopping distance the answer is:

         x = 0.686 m

Kinematics studies the motion of bodies, giving relationships between position, velocity and acceleration, let's use the relationship.  

            v² = v₀² - 2 a x

Where v is the velocity, v₀ the initial velocity, at the acceleration x the distance traveled

The reference system of units are coordinate systems selected by convention to exchange magnitudes with precision and reliability, the most used system is the international system of measurements (SI), let's reduce the magnitudes

            v₀ = 110 mi / h (1609.34 m / 1 mi) (1h / 3600s) = 49.17 m /s

This case as the car stops its final speed is zero  

          0 = v₀² - 2a x

          x = v₀² / 2a

We calculate

           x = 49.17² / 2 1762

           x = 0.686 m

In conclusion using kinematics we can find that for the braking distance the answer is:

         x = 0.686 m

Learn more here:

https://brainly.com/question/11910853

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