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Find two numbers given that their sum is 60 and
the smaller number is equal to 1/4of the larger one

Sagot :

Answer:

12 and 48

Step-by-step explanation:

let n be the larger number , then [tex]\frac{1}{4}[/tex] n is the smaller number and their sum is

x + [tex]\frac{1}{4}[/tex] x = 60 ( multiply through by 4 to clear the fraction )

4x + x = 240 , that is

5x = 240 ( divide both sides by 5 )

x = 48

smaller number = [tex]\frac{1}{4}[/tex] × 48 = 12

The 2 numbers are 12 and 48

Cece5351idn
12 and 48 is the answer
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