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find
[tex]value \: of \: x \\ 4 {x}^{2} + 5x + 6x = 3x - 2 {x}^{2} + x \\ [/tex]
fast please ​

Sagot :

Spammingallowedidn

Step-by-step explanation:

[tex]4 {x}^{2} + 5x + 6x = 3x - 2 {x}^{2} + x \\ 4 {x}^{2} + 11x = 4x - 2 {x}^{2} \\ 4 {x}^{2} + 2 {x}^{2} = 4x - 11x \\ 6 {x}^{2} = - 7x \\ 6x = - 7 \\ x = \frac{ - 7}{6} \\ thank \: you[/tex]

Coldprinceidn

Answer:

[tex] \rm x = -\frac{7}{6}[/tex]

Step-by-step explanation:

[tex] \rm 4 {x}^{2} + 5x + 6x = 3x - 2 {x}^{2} + x [/tex]

[tex] \rm 4x^{2}+11x=3x^{1}-2x^{2}+x [/tex]

[tex] \rm 4x^{2}+11x=3x-2x^{2}+x [/tex]

[tex] \rm 4x^{2}+11x=4x-2x^{2} [/tex]

[tex] \rm 4x^{2}+11x-4x=-2x^{2} [/tex]

[tex] \rm 4x^{2}+7x=-2x^{2} [/tex]

[tex] \rm 4x^{2}+7x+2x^{2}=0 [/tex]

[tex] \rm 6x^{2}+7x=0 [/tex]

[tex] \rm 6x + 7 = 0[/tex]

[tex] \bold{x = -\frac{7}{6}}[/tex]

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