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A custodian pushes a 119 kg box across a level floor. The box moves at a constant velocity. The custodian pushes horizontally on the box with a force of 724 Newtons, what must be the friction force experienced by the box in Newtons?

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Abidemiokinidn

The friction force experienced by the box in Newtons is 724N

The frictional force is the force that opposes the moving force acting on a body on a horizontal plane.

  • For a static body, the acceleration will be zero,

According to Newton's second law of motion:

  • ∑Fx = ma
  • +Fm - Ff = ma

Given the following paramters

  • Moving force Fm = 724N
  • acceleration a = 0m/s²
  • mass m = 119 kg

Substitute the given parameters into the formula to get the frictional force:

724 - Ff = 119(0)

724 - Ff = 0

Ff = 0 + 724

Ff = 724N

Hence the friction force experienced by the box in Newtons is 724N

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