Answered

Join the IDNLearn.com community and get your questions answered by knowledgeable individuals. Ask any question and receive comprehensive, well-informed responses from our dedicated team of experts.

The length of a rectangle is twice it’s width. If the area of the rectangle is 162m ^2,find its perimeter

Sagot :

Answer:

[tex]{ \tt{area = length \times width}} \\ { \tt{162 = 2w \times w}} \\ { \tt{162 = 2 {w}^{2} }} \\ { \tt{ {w}^{2} = 81}} \\ { \tt{w = 9}}[/tex]

  • width, w = 9 m
  • length, l = 2 × 9 = 18 m

[tex]{ \tt{perimeter = 2(l + w)}} \\ { \tt{p = 2(18 + 9)}} \\ { \tt{p = 2 \times 27}} \\ \\ { \underline{ \tt{ \: \: perimeter = 54 \: m \: \: }}}[/tex]

Coldprinceidn

Answer:

54 m

Step-by-step explanation:

First, find the width

　162 = 2w × w

　162 = 2w²

　w² = 162 ÷ 2

　w = [tex] \sqrt{81}[/tex]

　w = 9 m

┈

Second, find the length

　l = w × 2

　l = 9 × 2

　l = 18 m

┈

Then, find the perimeter

　perimeter = 2(l + w)

　perimeter = 2(18 + 9)

　perimeter = 2(27)

　perimeter = 54 m

We value your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your reliable source for answers. We appreciate your visit and look forward to assisting you again soon.