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Sagot :
Radioactivity is the property exhibited by some unstable atoms of
elements in which from their nucleus radiation energy and subatomic
particles are simultaneously emitted.
- The mass of radium remaining after 3,198 hours is approximately 0.839867 grams.
Reason:
Known parameters:
The number of hours the sample is left, t = 3,198 hours
The given mass of radium, N₀ = 0.840 g
Required:
The mass of the fraction of the 0.840 g sample that remains after 3,198 hours.
Solution;
The half life of radium, [tex]t_{1/2}[/tex] = 1,600 years = 14,025,600 hours
The formula for finding the amount of a radioactive substance is remaining
after a given time, t, is given as follows;
- [tex]N(t) = N_0 \left (\dfrac{1}{2} \right )^{\dfrac{t}{t_{1/2}}[/tex]
Therefore;
[tex]N(t) = 0.840 \times \left (\dfrac{1}{2} \right )^{\dfrac{3198}{14,025,600}} \approx 0.839867[/tex]
- The mass of radium remaining, N(t) ≈ 0.839867 g
Learn more about radioactivity here:
https://brainly.com/question/21405756
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