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The expression 2x−(2x+3)2+4(x−1)+x3 can be simplified into the form Ax3+Bx2+Cx+D. Find the missing constants A, B, C, and D below.

Sagot :

Hi1315idn

Answer:

Step-by-step explanation:

Before solving this we  have to know that,

(-) ×(-)=(+)

(+)×(+) =(+)

(+)×(-)=(-)

Lets solve now,

[tex]2x-(2x+3)2+4(x-1)+x^{3} \\2x-(2x-3)^{2} +4x-4+x^{3} \\2x-(4x^{2} -12x+9)+4x-4+x^{3} \\2x-4x^{2} +12x-9+4x-4+x^{3} \\2x+12x+4x-4x^{2} -9-4+x^{3} \\14x-4x^{2} -13+x^{3} \\\\So,\\x^{3} -4x^{2} +14x-13\\\\Therefore,\\A = 1\\B = (-4)\\C = 14\\D = (-13)[/tex]

Hope this helps you

Let me know if you have any other questions :-)

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