Answer:
43.5m
Step-by-step explanation:
In triangles ABC and BCD, the common side is the adjacent side BC.
BD= 50 -1.5
BD= 48.5m
Triangle BCD
opp= BD= 48.5m
θ= 37°
[tex]\boxed{tanθ = \frac{opp}{adj} }[/tex]
[tex]tan37° = \frac{48.5}{BC} [/tex]
BC= 48.5 tan37°
BC= 36.547m (5 s.f.)
Triangle ABC
adj= BC= 36.547m
θ= 49°
[tex] \tan49° = \frac{AB}{BC} [/tex]
AB= BC tan49°
AB= 36.548 tan49°
AB= 42.044m (5 s.f.)
Height of tower
= AB +1.5
= 42.044 +1.5
= 43.5m (nearest tenth)
